2603 has the prime factors 19 x 137 which further decompose into (102 – 92) x (42 + 112). Therefore the rubric states: ‘puzzle NUMBER is BRACKET TEN SQUARED MINUS NINE SQUARED BRACKET TIMES BRACKET FOUR SQUARED PLUS ELEVEN SQUARED BRACKET’.
First prize John Bennett, Havant, Hants
Runners-up Julie Sanders, Bishops Waltham, Southampton; Richard Andrews, Ashford, Middlesex
Got something to add? Join the discussion and comment below.
Already a subscriber? Log in
Get 10 issues
for $20
Subscribe to The Spectator Australia today for the next 10 magazine issues, plus full online access, for just $20.
- Delivery of the weekly magazine
- Unlimited access to spectator.com.au and app
- Spectator podcasts and newsletters
- Full access to spectator.co.uk
Or
Unlock this article
You might disagree with half of it, but you’ll enjoy reading all of it. Try your first month for free, then just $2 a week for the remainder of your first year.
Comments
Don't miss out
Join the conversation with other Spectator Australia readers. Subscribe to leave a comment.
SUBSCRIBEAlready a subscriber? Log in